I am trying to write a regular expression that will only allow lowercase letters and up to 10 characters. What I have so far looks like this:
pattern: /^[a-z]{0,10}+$/
This does not work or compile. I had a working one that would just allow lowercase letters which was this:
pattern: /^[a-z]+$/
But I need to limit the number of characters to 10.
You can use curly braces to control the number of occurrences. For example, this means 0 to 10:
/^[a-z]{0,10}$/
The options are:
See the regular expression reference.
Your expression had a + after the closing curly brace, hence the error.
^
to property match ONLY requests with a name like 1234
or 5678
, and I had to include the $ sig - Devin G Rhode 2018-06-07 22:30
/^[a-z]{0,10}$/
should work. /^[a-z]{1,10}$/
if you want to match at least one character, like /^[a-z]+$/
does.
It might be beneficial to add greedy matching to the end of the string, so you can accept strings > than 10 and the regex will only return up to the first 10 chars. /^[a-z0-9]{0,10}$?/
grep '^[0-9]\{1,16\}' | wc -l
Gives the counts with exact match count with limit