I want to evaluate the integral of this function :
over the period
I am using these :
f=@(t) (cos(t.^2).*sin(t).^2).^(1/2); quad(f,-15*pi,50*pi)
But i am getting warned:
Warning: Maximum function count exceeded; singularity likely. > In quad at 110 In PPEL at 6 ans = 35.8252 +54.5673i
Most likely there is something stupid that i don't know about the theoretical part of the math, like some singularity as MATLAB said.
Moreover, when i want to evaluate this function sybolically with this :
It says : Warning: Explicit integral could not be found.
ans = int((cos(t^2)*sin(t)^2)^(1/2), t)
What's the solution ?
Plot the function without trying to do the integral.
What I notice is that you are going to be taking the square root of a negative number. I suspect that that isn't what you want to be doing...